close
標題:

4^x+6^x =9^x, find x

免費註冊體驗

 

此文章來自奇摩知識+如有不便請留言告知

發問:

4^x+6^x =9^x, find x. Please help me

最佳解答:

4^x+6^x=9^x As 6^x>0 for real x, we can divide the equation by 6^x and get (4/6)^x+1=(9/6)^x (2/3)^x+1=(3/2)^x Let y=(2/3)^x, we get y+1=1/y y^2+y=1 y^2+y-1=0 y=(±√5-1)/2 As y=(2/3)^x>0 for real x, we get y=(√5-1)/2 As y=(2/3)^x, we get ln y =x ln (2/3) x =ln y / ln (2/3)= ln [(√5-1)/2] / ln (2/3)=1.1868

其他解答:

If you plot 4^x+6^x-9^x against x, you will notice a root at x=1.1865 (approx.). Zoomed in image at: http://i263.photobucket.com/albums/ii157/mathmate/4x_6x-1.png Using this information, you can refine the solution by rewriting the equation as xlog9=log(4^x+6^x) x=log(4^x+6^x)/log9 Starting with x=1.187 on the right hand side, and repeatedly substituting the new value of x on the RHS, we get successively: x1=1.186952665878328 x2=1.186917402828997 x3=1.186891132532082 Using Shank's transformation on x1,x2 and x3, we obtain x=(x1*x3-x2^2)/(x1+x3-2*x2)=1.186814389796409 accurate to 8 places of decimal. The accurate solution is: 1.186814390280981
arrow
arrow
    創作者介紹
    創作者 yffuhxy 的頭像
    yffuhxy

    yffuhxy的部落格

    yffuhxy 發表在 痞客邦 留言(0) 人氣()