標題:
2條問題a0a math
[IMG]http://i293.photobucket.com/albums/mm67/zaza520/0004-13.jpg[/IMG] 唔該>vvvv<
最佳解答:
(12) (a) a = 100 - 35 - 25 = 40 cm b = 180 - 82 - 38 = 60度 (b) △MNL ~ △POQ, 因為 MN/PO = NL/OQ = 5/8 及 ∠MNL = ∠POQ. (13) (a) AC = 63 - 8 - 10 - 18 - 15 = 12 cm (b) △ABC ~ △CAD, 因為 AB/CA = BC/AD = CA/DC = 2/3
其他解答:
(12) (a) 周界LMN = 100 a = 100 -25-35 = 40units b = 180 - 82 - 38 = 60 (b) by sine law: PQ / sin b = OQ / sin 82 PQ = 64 sin 60 / sin 82 = 60 units PO / MN = 40 / 25 = 1.6 QP / LM = 56 / 35 = 1.6 QO / LN = 64 / 40 = 1.6 The ratio for each side are the same. The triangle LMN is similar with triangle QPO (13) (a) AC = 63 - AD - DC -AB - BC = 63 -15 - 18 - 8 - 10 = 12 units (b) consider triangle ABC and triangle ACD BA / AC = 8 / 12 = 2/3 BC / AD = 10 / 15 = 2/3 AC / CD = 12 / 18 = 2/3 The ratio for each side are the same. The triangle ABC is similar with triangle ACD
2條問題a0a math
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發問:[IMG]http://i293.photobucket.com/albums/mm67/zaza520/0004-13.jpg[/IMG] 唔該>vvvv<
最佳解答:
(12) (a) a = 100 - 35 - 25 = 40 cm b = 180 - 82 - 38 = 60度 (b) △MNL ~ △POQ, 因為 MN/PO = NL/OQ = 5/8 及 ∠MNL = ∠POQ. (13) (a) AC = 63 - 8 - 10 - 18 - 15 = 12 cm (b) △ABC ~ △CAD, 因為 AB/CA = BC/AD = CA/DC = 2/3
其他解答:
(12) (a) 周界LMN = 100 a = 100 -25-35 = 40units b = 180 - 82 - 38 = 60 (b) by sine law: PQ / sin b = OQ / sin 82 PQ = 64 sin 60 / sin 82 = 60 units PO / MN = 40 / 25 = 1.6 QP / LM = 56 / 35 = 1.6 QO / LN = 64 / 40 = 1.6 The ratio for each side are the same. The triangle LMN is similar with triangle QPO (13) (a) AC = 63 - AD - DC -AB - BC = 63 -15 - 18 - 8 - 10 = 12 units (b) consider triangle ABC and triangle ACD BA / AC = 8 / 12 = 2/3 BC / AD = 10 / 15 = 2/3 AC / CD = 12 / 18 = 2/3 The ratio for each side are the same. The triangle ABC is similar with triangle ACD
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