標題:
有數學唔識做
發問:
(+6)x(-3) (-48)÷(-12) (-4)x(-3)÷(+4) 4-6x2-27÷3 (2-8)x3+(-16)÷(-4) (-7)x [12-5x(-7)] 7分之3÷(5分之-6)-(-7分之2)x3分之4 要有過程
最佳解答:
(+6)x(-3) = -18 因為正負得負 (-48)(-12) =4 因為負負得正 (-4)x(-3)÷(+4) =12÷4 =3 4-6x2-27÷3 =4-(6x2)-(27÷3) 先乘除,後加減 =4-12-9 =-17 (2-8)x3+(-16)÷(-4) =(-6)x3 + 4 =-18+4 =-14 (-7)x [12-5x(-7)] =(-7)x (12+35) =-7x47 =-329 7分之3÷(5分之-6)-(-7分之2)x3分之4 (好難寫過程) 如果冇錯,,應該係1/42
其他解答:
(+6)x(-3) = -18 (-48)÷(-12) =4 (-4)x(-3)÷(+4) = 12÷4 = 3 4-6x2-27÷3 = 4-12-9 = -8-9 = -17 (2-8)x3+(-16)÷(-4) = -6x3+4 = -18+4 = -14 (-7)x [12-5x(-7)] = -7x [12-(-35)] = -7x (12+35) = -7x47 = -329 7分之3÷(5分之-6)-(-7分之2)x3分之4 =3/7x 5/-6 - (2/-7)x 4/3 = 5/-14 -(8/-21) = 1/42 =42分之1 最後個條如果你冇講錯d分數就應該岩喇 你係咪F.1呀? d數自己試下做啦.. 我比左d答案你都希望你個睇下d過程係點做.. 學野係靠自己架 下次自己做下先啦=)
有數學唔識做
發問:
(+6)x(-3) (-48)÷(-12) (-4)x(-3)÷(+4) 4-6x2-27÷3 (2-8)x3+(-16)÷(-4) (-7)x [12-5x(-7)] 7分之3÷(5分之-6)-(-7分之2)x3分之4 要有過程
最佳解答:
(+6)x(-3) = -18 因為正負得負 (-48)(-12) =4 因為負負得正 (-4)x(-3)÷(+4) =12÷4 =3 4-6x2-27÷3 =4-(6x2)-(27÷3) 先乘除,後加減 =4-12-9 =-17 (2-8)x3+(-16)÷(-4) =(-6)x3 + 4 =-18+4 =-14 (-7)x [12-5x(-7)] =(-7)x (12+35) =-7x47 =-329 7分之3÷(5分之-6)-(-7分之2)x3分之4 (好難寫過程) 如果冇錯,,應該係1/42
其他解答:
(+6)x(-3) = -18 (-48)÷(-12) =4 (-4)x(-3)÷(+4) = 12÷4 = 3 4-6x2-27÷3 = 4-12-9 = -8-9 = -17 (2-8)x3+(-16)÷(-4) = -6x3+4 = -18+4 = -14 (-7)x [12-5x(-7)] = -7x [12-(-35)] = -7x (12+35) = -7x47 = -329 7分之3÷(5分之-6)-(-7分之2)x3分之4 =3/7x 5/-6 - (2/-7)x 4/3 = 5/-14 -(8/-21) = 1/42 =42分之1 最後個條如果你冇講錯d分數就應該岩喇 你係咪F.1呀? d數自己試下做啦.. 我比左d答案你都希望你個睇下d過程係點做.. 學野係靠自己架 下次自己做下先啦=)
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