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這是我的數學報告問題有一些我不大會可以請各為大大幫我解答嗎謝謝Q1. A witness has stated that she saw the suspect get into another car and proceed north at a constant speed of 100km/h. Thesuspect has already gone 20km when you set off north at a constant speed of 120km/h.a) Write an equation for the distance travelled by the... 顯示更多 這是我的數學報告問題 有一些我不大會 可以請各為大大幫我解答嗎 謝謝 Q1. A witness has stated that she saw the suspect get into another car and proceed north at a constant speed of 100km/h. Thesuspect has already gone 20km when you set off north at a constant speed of 120km/h. a) Write an equation for the distance travelled by the suspect t hours after you started the pursuit. b) Define each of the unknowns c) write an equations for the distance you have travelled in pursuit after t hours. d) Define each of the unknowns e) Draw a distance-time graphs for the suspect and your pursuit vehicle on the same set of axis. f)How much time elapses before you overtake the suspect? Q2. Later that evening you are notified that a robbery is occuring in a town 105km away. You are called in to investigate and travel at120 km/h to the town. a) Write an equation for the distance you are from the town t hours after being called. b) Draw the distance- itne graph. c) How many mins after being called do you arrive in the town? The criminals are (unknowingly) travelling at 80km/h from the town directly towards you. When and where will you meet the criminal's car?
最佳解答:
圖片參考：http://www.badongo.com/t/250/3574410 Q1: (a) 100t + 20 = 120 t (b) t is the only unknown. the time elapsed before catching. (c) 120 t is the distance travelled t hours after pursue (e) Please see the picture above (f) solve the equation. We got t = 1. After one hour, I can catch the suspect Q2: (a) 105 = 120 t (b) as shown above (c) 105 / 120 * 60 = 52.5 minutes (d) 120t + 80 t = 105 when: t = 0.525 hours = 31.5 minutes where: 120 * 0.525 = 63 km from where you started or 80 * 0.525 = 42 km away from town
其他解答:
(1) D1: the distance travelled by the suspect t hours after you started the pursuit(including 20km he had gone before you set off) D1 = 20+100t D2:the distance you have travelled in pursuit after t hours D2 = 120t 畫 (t-d 圖, t為水平軸, d 為垂直軸) D1 = D2 => 20 + 100t = 120t => t = 1 hr. 2008-05-13 18:01:31 補充： D3:the distance you are from the town t hours after being called D3 = 105 - 120t 畫 t-d 圖( (3) 0 = 105-120t = t = 52.5/60 hr. = 52.5 min. (4) D4:the distance the criminal are from the town t hours after you are called D4 = 80t D4 =D3 => 105-120t = 80t => t = 21/40 hr => D4=D3=42km from the town 2008-05-13 18:04:45 補充： 為符合二元一次方程式的標準寫法 上述 D1,D2,D3,D4 都應用 d 表示 d= 20+100t d = 120t d = 105 - 120t d = 80t7C4150FCDCEDD023
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Maths ASSIGMENT發問:
這是我的數學報告問題有一些我不大會可以請各為大大幫我解答嗎謝謝Q1. A witness has stated that she saw the suspect get into another car and proceed north at a constant speed of 100km/h. Thesuspect has already gone 20km when you set off north at a constant speed of 120km/h.a) Write an equation for the distance travelled by the... 顯示更多 這是我的數學報告問題 有一些我不大會 可以請各為大大幫我解答嗎 謝謝 Q1. A witness has stated that she saw the suspect get into another car and proceed north at a constant speed of 100km/h. Thesuspect has already gone 20km when you set off north at a constant speed of 120km/h. a) Write an equation for the distance travelled by the suspect t hours after you started the pursuit. b) Define each of the unknowns c) write an equations for the distance you have travelled in pursuit after t hours. d) Define each of the unknowns e) Draw a distance-time graphs for the suspect and your pursuit vehicle on the same set of axis. f)How much time elapses before you overtake the suspect? Q2. Later that evening you are notified that a robbery is occuring in a town 105km away. You are called in to investigate and travel at120 km/h to the town. a) Write an equation for the distance you are from the town t hours after being called. b) Draw the distance- itne graph. c) How many mins after being called do you arrive in the town? The criminals are (unknowingly) travelling at 80km/h from the town directly towards you. When and where will you meet the criminal's car?
最佳解答:
圖片參考：http://www.badongo.com/t/250/3574410 Q1: (a) 100t + 20 = 120 t (b) t is the only unknown. the time elapsed before catching. (c) 120 t is the distance travelled t hours after pursue (e) Please see the picture above (f) solve the equation. We got t = 1. After one hour, I can catch the suspect Q2: (a) 105 = 120 t (b) as shown above (c) 105 / 120 * 60 = 52.5 minutes (d) 120t + 80 t = 105 when: t = 0.525 hours = 31.5 minutes where: 120 * 0.525 = 63 km from where you started or 80 * 0.525 = 42 km away from town
其他解答:
(1) D1: the distance travelled by the suspect t hours after you started the pursuit(including 20km he had gone before you set off) D1 = 20+100t D2:the distance you have travelled in pursuit after t hours D2 = 120t 畫 (t-d 圖, t為水平軸, d 為垂直軸) D1 = D2 => 20 + 100t = 120t => t = 1 hr. 2008-05-13 18:01:31 補充： D3:the distance you are from the town t hours after being called D3 = 105 - 120t 畫 t-d 圖( (3) 0 = 105-120t = t = 52.5/60 hr. = 52.5 min. (4) D4:the distance the criminal are from the town t hours after you are called D4 = 80t D4 =D3 => 105-120t = 80t => t = 21/40 hr => D4=D3=42km from the town 2008-05-13 18:04:45 補充： 為符合二元一次方程式的標準寫法 上述 D1,D2,D3,D4 都應用 d 表示 d= 20+100t d = 120t d = 105 - 120t d = 80t7C4150FCDCEDD023
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