標題:
F.1 Maths題,急
發問:
Concert ticket in $400, $200 and $100 each are available for sale.The number of $200 tickets sold is 4 times as many as that of $400 ticket.The number of $100 tickets sold is 380 more than that of $200 tickets.If the total income from the sale of tickets is $86 000,how many $400 tickets are... 顯示更多 Concert ticket in $400, $200 and $100 each are available for sale.The number of $200 tickets sold is 4 times as many as that of $400 ticket.The number of $100 tickets sold is 380 more than that of $200 tickets.If the total income from the sale of tickets is $86 000,how many $400 tickets are sold? 答案為30.但我唔知點列式,請提供列式,最好有埋中文意思. 更新: KC,但係根據''The number of $100 tickets sold is 380 more than that of $200 tickets.'' $200 tickets唔係比$400 ticket多4倍咩,咁100 tickets唔係$400 ticket的4倍多$380咩?
最佳解答:
演唱會有400元,200元,100元的門票售賣.賣出的200元門票數量是400元門票的4倍,賣出的100元門票又比200元的多380張.如果賣出門票的總收入是86000元,請問賣出了多少張400元門票 Let y be the number of the sold $400 tickets 400y+4x200y+4x100y+380x100=86000 400y+800y+400y=48000 1600y=48000 y=30
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演唱會有400元,200元,100元的門票售賣.賣出的200元門票數量是400元門票的4倍,賣出的100元門票又比200元的多380張.如果賣出門票的總收入是86000元,請問賣出了多少張400元門票 Let y be the number of the sold $400 tickets 400y+4x200y+4x100y+380x100=86000 400y+800y+400y=48000 1600y=48000 y=30|||||Let Q be the number of $400 tickets, Q×4×200+(Q×4+380)×100+400Q=86000 800Q+400Q+38000+400Q=86000 (800+$400+400)Q=86000－38000 1600Q=48000 Q=48000÷1600 Q=30 ∴30 $400 tickets are sold 如果明白,可以跳steps|||||當$400 售出左既tickets 既數目為X , $200 tickets 為Y ,$100 為z y=4x 因為200蚊既票係 4倍(4times) 既X ($400) z = y +380 因為100蚊(Z)門票係多過200蚊(Y)既門票380張 收入 400X + 200Y + 100Z = 86000 全式除100 4x+ 2y + z =860 因y =4x z = y +380 所以 y + 2y + y +380 = 860 y= 120 擺y=120 落 y = 4x x = 30 $400蚊門票係30張6FE1C172A843305D
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